Question

(4x+5)(4x-1) solution ​

Answer 1

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Answer 2

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$By, \:using \:this\: identity.......\\ (x + a)(x + b) = {x}^{2} + (a + b)x + ab \\ \\ so......... \\ (4x + 5)(4x - 1) \\ = {(4x)}^{2} + (5 + ( - 1))4x + (5)( - 1) \\ = 16 {x}^{2} + (5 - 1)4x + ( - 5) \\ = 16 {x}^{2} + 4 \times 4x - 5 \\ = 16 {x}^{2} + 16x - 5$