Question

(4x-5) (x-2) =0 by splitting middle term
...its very urgent please ☹️
answer​

Answer 1

$\tt{(4x - 5)(x - 2) = 0}$

$\tt{4x(x - 2) - 5(x - 2) = 0}$

$\tt{4 {x}^{2} - 8x - 5x + 10 = 0 }$

$\tt{4 {x}^{2} - 13x + 10 = 0 }$

$\tt{4 {x}^{2} - 8x - 5x + 10 = 0 }$

$\tt{4x(x - 2) - 5(x - 2) = 0}$

$\tt{(4x - 5)(x - 2) = 0}$

$\tt{4x = 5 \: and \: { \boxed{x = 2}}}$

$\tt{x = \frac{5}{4} }$

Hope my answer will help you.