Question

4x-5y+16=0, 2x+y-6=0 ?
(by replacement method)​

Answer 1

Answer:

4x-5y+16=0......... (1)

2x+y-6=0 ............( 2)

multiply eq. (2)by 5

we get

5(2x+y-6)= 5x0 ............( 2)

=10X +5y-30=0.........(3)

adding eq. (1) and (3)

4x-5y+16 +10X +5y-30 = 0 +0

=> 14x-I4 = 0

=> 14x = 14

So, X=1

Putling the value of X in eq. (1)

4x-5y+16=0

4X1-5y + 16=O

=> 4 - 5 y+16=0

=>- 5 y= -20

So, y=4