Question

4x-5y+16=0 and 2x+y-6=0
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Answer 1

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$4x - 5y + 16 = 0$

$x = \frac{16 + 5y}{4}$

put value of x in another equation

$2( \frac{16 + 5y}{4} ) + y - 6 = 0$

$\frac{32 + 10y}{4} + y - 6 = 0$

$32 + 10y + 4y - 24 = 0$

$14y + 8 = 0$

$14y = - 8$

$y = - \frac{8}{14} = - \frac{4}{7}$

put y value in

$x = \frac{32 + 10 \times - \frac{4}{7} }{4} = 8 + 10 \times - \frac{4}{7}$

$18 \times - \frac{4}{7} = - \frac{72}{7}$

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Answer 2

Step-by-step explanation:

Answer:

Refer the attached graph below.

Step-by-step explanation:

Given : Equation - 4x-5y + 16 = 04x−5y+16=0 and 2x + y = 62x+y=6

To draw : The graph of the given equation and determine the vertices of the triangle formed by these lines and the x-axis.

Solution :

The graph of two equation is drawn.

Refer the attached figure below.

The line of4x -5y + 16 = 04x−5y+16=0 red in color passing through points (0,3.2) and (-4,0).

The line of 2x + y = 62x+y=6 blue in color passing through points (0,6) and (3,0).

The intersection of these two lines is at the point (1,4).

The solution of two graph is (1,4).

The vertices of the triangle formed by these lines and the x-axis is (-4,0) and (3,0)