Math, asked by gauri314, 6 months ago

4x-5y+16=0 and 2x+y-6=0

Answers

Answered by Anonymous
158

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\red{\bold{\underline{\underline{❥Question᎓}}}}4x-5y+16=0 and 2x+y-6=0

Answer:

4x - 5y + 16 = 0

x = \frac{16 + 5y}{4}

\bold{put\: value\: of\: x\: in \:another \:equation}

2( \frac{16 + 5y}{4} ) + y - 6 = 0

 \frac{32 + 10y}{4} + y - 6 = 0

32 + 10y + 4y - 24 = 0

14y + 8 = 0

14y = - 8

\bold{y = - \frac{8}{14} = - \frac{4}{7} }[/</p><p>tex]</p><p>[tex]\bold{put\: y \:value\: in }

x = \frac{32 }+ 10 \times - \frac{4}</p><p>{7} {4} = 8 + 10 \times - \frac{4}{7}

18 \times - \frac{4}{7} = - \frac{72}{7}

Hope it helps you..!!!

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