Question

4x-5y+16=0 and 2x+y-6=0

Answer 1

$\huge{\bold☘}\mathfrak\pink{\bold{\underline{{ ℘ɧεŋσɱεŋศɭ}}}}{\bold☘}$

$\red{\bold{\underline{\underline{❥Question᎓}}}}$4x-5y+16=0 and 2x+y-6=0

Answer:

⟹$4x - 5y + 16 = 0$

⟹ $x = \frac{16 + 5y}{4}$

$\bold{put\: value\: of\: x\: in \:another \:equation}$

⟹ $2( \frac{16 + 5y}{4} ) + y - 6 = 0$

⟹ $\frac{32 + 10y}{4} + y - 6 = 0$

⟹ $32 + 10y + 4y - 24 = 0$

⟹ $14y + 8 = 0$

⟹ $14y = - 8$

⟹ $y = - \frac{8}{14} = - \frac{4}{7} [/</p><p>tex]</p><p>[tex]\bold{put\: y \:value\: in }$

⟹ $\bold{x = \frac{32 }+ 10 \times - \frac{4}</p><p>{7} {4} = 8 + 10 \times - \frac{4}{7}}$

⟹ $18 \times - \frac{4}{7} = - \frac{72}{7}$

Hope it helps you..!!!

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Answer 2

Step-by-step explanation:

\huge{\bold☘}\mathfrak\pink{\bold{\underline{{ ℘ɧεŋσɱεŋศɭ}}}}{\bold☘}☘

℘ɧεŋσɱεŋศɭ

☘

\red{\bold{\underline{\underline{❥Question᎓}}}}

❥Question᎓

4x-5y+16=0 and 2x+y-6=0

Answer:

⟹4x - 5y + 16 = 04x−5y+16=0

⟹ x = \frac{16 + 5y}{4}x=

4

16+5y

\bold{put\: value\: of\: x\: in \:another \:equation}putvalueofxinanotherequation

⟹ 2( \frac{16 + 5y}{4} ) + y - 6 = 02(

4

16+5y

)+y−6=0

⟹ \frac{32 + 10y}{4} + y - 6 = 0

4

32+10y

+y−6=0

⟹ 32 + 10y + 4y - 24 = 032+10y+4y−24=0

⟹ 14y + 8 = 014y+8=0

⟹ 14y = - 814y=−8

⟹ y = - \frac{8}{14} = - \frac{4}{7} [/ tex] $\bold{put\: y \:value\: in }y=− </p><p>14</p><p>8</p><p> </p><p> =− </p><p>7</p><p>4</p><p> </p><p>$[tex]putyvaluein

⟹ \bold{x = \frac{32 }+ 10 \times - \frac{4} {7} {4} = 8 + 10 \times - \frac{4}{7}}x=

+

32

10×−

7

4

4=8+10×−

7

4

⟹ 18 \times - \frac{4}{7} = - \frac{72}{7}18×−

7

4

=−

7

72

Hope it helps you..!!!

________________

THANKYOU