Question

4x-5y+16=0 and 2x+y-6=0

Answer 1

$\huge{\bold☘}\mathfrak\pink{\bold{\underline{{ ℘ɧεŋσɱεŋศɭ}}}}{\bold☘}$

$\red{\bold{\underline{\underline{❥Question᎓}}}}$4x-5y+16=0 and 2x+y-6=0

Answer:

⟹$4x - 5y + 16 = 0$

⟹ $x = \frac{16 + 5y}{4}$

$\bold{put\: value\: of\: x\: in \:another \:equation}$

⟹ $2( \frac{16 + 5y}{4} ) + y - 6 = 0$

⟹ $\frac{32 + 10y}{4} + y - 6 = 0$

⟹ $32 + 10y + 4y - 24 = 0$

⟹ $14y + 8 = 0$

⟹ $14y = - 8$

⟹ $y = - \frac{8}{14} = - \frac{4}{7} [/</p><p>tex]</p><p>[tex]\bold{put\: y \:value\: in }$

⟹ $\bold{x = \frac{32 } 10 \times - \frac{4}</p><p>{7} {4} = 8 + 10 \times - \frac{4}{7} }$

⟹ $18 \times - \frac{4}{7} = - \frac{72}{7}$

Hope it helps you..!!!

________________

THANKYOU

Answer 2

\huge{\bold☘}\mathfrak\pink{\bold{\underline{{ ℘ɧεŋσɱεŋศɭ}}}}{\bold☘}☘

℘ɧεŋσɱεŋศɭ

☘

\red{\bold{\underline{\underline{❥Question᎓}}}}

❥Question᎓

To factorise m^2-4m+33

\huge\tt\underline\blue{「Answer」 }

「Answer」

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_ _ _ _ _ _ _ _ _ _ _ _ _ _ _✍️

{m}^{2} - 4 m + 33m

2

−4m+33

Here we use quadratic formula to find out the roots:-

\bold{Here\: ,a=1\: ,b=-4 & c=33}

⟹m = \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}⟹m=

2a

−b±

b

2

−4ac

⟹ m= \frac{ - ( - 4)±\sqrt{ {( - 4)}^{2} - 4(1)(33)} }{2(1)}⟹m=

2(1)

−(−4)±

(−4)

2

−4(1)(33)

⟹m= \frac{4± \sqrt{16 - 132} }{2}⟹m=

2

4±

16−132

⟹m = \frac{4± \sqrt{ - 116} }{2} = \frac{4±2 \sqrt{ - 29} }{2}⟹m=

2

4±

−116

=

2

4±2

−29

⟹m = \frac{2(2± \sqrt{ - 29} )}{2} = 2± \sqrt{29i}⟹m=

2

2(2±

−29

)

=2±

29i

\bold{Here\: is\: your\: answer}Hereisyouranswer

i(we say iota is placed of -ve sign whenever inside the root value so we simply replace negative sign by placing iota instead of negative sign inside roots)

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