Math, asked by gotomugshots, 6 hours ago

(4x+5y)^2-80xy=(4x-5y)^2

Answers

Answered by rajutkarsh938686
1

here is your answer

4x+5y)^2-80xy=(4x-5y)^2

16x^2+40xy+25y^2-80xy=16x^2-40xy+25y^2

16x^2-40xy+25y^2=16x^2-40xy+25y^2

0

Step-by-step explanation:

mark me as brainleist answer please

Similar questions
Math, 8 months ago