Math, asked by suman6614, 8 hours ago

4x+5y=20 find the value of y when x =0 in this equation write any two solution of the equation 4x +y=7

Answers

Answered by rainstar720
5

Answer:

value of y when x=0 is y=4

solution of the equation 4x+y=7 are x=0, y=7

and x=1, y=3

Step-by-step explanation:

To find the value of y when x=0, put x=0 in the equation 4x+5y=20

=> 4*0+5y=20

=> 5y=20

=> y=20/5 =4

=> y=4

To find any two solution of the equation 4x+y=7

first put any value corresponding to x and substitute in the equation just like the above method, you will get the corresponding value of y.

It will be ome of the solution of that equation.

similarly take any other value of x and you will get the second pair of the solution.

Answered by pramilasarkar
4

Solution:

4x+5y=20

we take x=0

4x0+5y=20

5y=20

y=4

Therefore, the solution of the given equation is (x,y) = (0,4)

4x+y=7

let us take a corresponding value of x as x=1

4x+y=7

4(1)+y=7

4+y=7

y=7-4

y=3

therefore, (x,y)= (1,3)

let us take the value of x=0

4x+y=7

4(0)+y=7

4+y=7

y=3

therefore, (x,y) = (0,3)

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