Question

4x-5y=39 ; 2x-7y=51 by substitution and find the value of y before x

Answer 1

HLO MATE ✋✋
Simran Here !!!

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⏩ 4x - 5y = 39 ----------(i)
⏩ 2x - 7y = 51 ----------(ii)

USING SUBSTITUTION METHOD :

From Equation (i)
4x - 5y = 39
4x = 39 + 5y
x = 39 + 5y/ 4 ---------(iii)

PUTTING the value of 'x' in equatin (ii)
2x - 7y = 51
2(39 + 5y/4) - 7y = 51
78 + 10y - 28y = 204
-18y = 204 - 78
- 18y = 126
y = -126/18
y = - 7

NOW ,
PUTTING the value of 'y' in equation (iii)
x = 39 + 5y/4
x = 39 + 5(-7)/4
x = 39 - 35 /4
x = 4/4
x = 1

So, The value of y before x is -7✔✔
& The value of x is 1 ✔
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Answer 2

here's ur answer
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