Question

4x-5y=k 3x-3y=12 find the k ​

Answer 1

=> 4x - 5y = k

Here, a^1 = 4, b^1 = -5, and c^1 = k

=> 2x - 3y = 12

Here, a^2 = 2' b^2 = -3, and c^2 = 12

For the two equations to have unique solutions,

a^1/a^2 ≠ b^1/b^2

Since k doesn't affect the condition for the equation to have a single solution, k can take any real value.

Therefore, k has any real value.

Answer 2

Answer:

For the system to have unique solution, lines must intersect each other

⇒it should be neither Parallel nor coincide each other

⇒ratio of respective coefficients must not be equal

⇒

2

4



=

3

5

⇒it is independent of k i.e, for all values of k, lines will intersect

⇒k∈(−∞,∞)

Step-by-step explanation:

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