Math, asked by shruthi5392, 7 months ago

(4x-6)-9/10(6x-14)=1​

Answers

Answered by jjguk
13

Answer:

Step-by-step explanation:

solution,

  (4x-6)-9/10(6x-14)=1​

or, 4x-6-9/60x-140 = 1

or, 4x-15/60x-140 = 1

or, 4x- 15 = 60x - 140

or, 60x - 4x = -140+15

or, 56x = -125

∴ x = -125/56

Answered by Anonymous
6

Answer:

Solution for (4x-6)-9/10(6x-14)=1 equation:

(4x-6)-9/10(6x-14)=1

We move all terms to the left:

(4x-6)-9/10(6x-14)-(1)=0

Domain of the equation: 10(6x-14)!=0

x∈R

We get rid of parentheses

4x-9/10(6x-14)-6-1=0

We multiply all the terms by the denominator

4x*10(6x-14)-6*10(6x-14)-1*10(6x-14)-9=0

Wy multiply elements

40x^2(6-60x(6-10x(6-9=0

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