Question

4x + 6 y = 15 and 6x − 8 y = 14, y ≠ 0. substitution method
Grade 10 Pair of Linear Equations in Two Variables.

Answer 1

Solution

Given :-

• Equation, 4x + 6y = 15_________(1)
• 6x - 8y = 14__________________(2)

Find :-

• Value of x & y by substitution method.

Explanation

Substitution Method

By, equ(1)

==> 4x = 15 - 6y

==> x = (15 - 6y)/4_____________(3)

keep in equ(2)

==> 6 × [ (15 - 6y)/4] - 8y = 14

==> 90 - 36y -32y = 56

==> 68y = 90 - 56

==> 68y = 34

==> y = 34/68

==> y = 1/2 .

keep value of y in equ(3)

==> x = ( 15 - 6×1/2)/4

==> x = (15 - 3)/4

==> x = 12/4

==> x = 3

Hence

• Value of x be = 3
• Value of y. be= 1/2.

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Verification Answer .

For, this keep value of x & y in equ(1)

==> 4×3 + 6×1/2 = 15

==> 12 + 3 =15

==> 15 = 15

L.H.S. =R.H.S.

That's Proved.

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