Question

(4x+7) (4x+9) using identity

Answer 1

$\mathcal{\huge{\underline{\boxed{\red{Answer:}}}}}$

$\bold{(4x+7) (4x+9)}$
=> (4x)^2 + [7+9]4x + (7)(9)
=> 16x^2 + 64x + 63

Hope helps...

Answer 2

hope it is helpful
pls mark it as brainliest!!!!