Question

4x-7y+28=0 , 7x-5y-9=0 solve using substitution method​

Answer 1

Step-by-step explanation:

4x-7y+28=0

4x-7y= (-28)

4x = (-28)+7y

x = (-28)+7y /4

7x-5y=9

$7( \frac{ - 28 + 7y}{4} ) - 5y = 9$

$(\frac{28 - 28 + 7y}{4} ) - 5y = 9$

$\frac{28 - 28 + 7y - 20y}{4} = 9$

$\frac{ - 13y}{4} = 9$

$- 13y = 36$

$y = ( - 3)$

4x-7y = (-28)

4x -7(-3) = (-28)

4x +21 = (-28)

4x = -49

x = -49/4

x = - 12.2

Hope this helped:)

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