Question

4x +7y=29;x+3y=11.....solve it by elimination​

Answer 1

Answer:

↪↪x=2 and y=3.........

Step-by-step explanation:

✏QUESTION↪

4x+7y=29,x+3y=11 find the value of x and y...

✏TO FIND➡➡value of x and y.

(using formula =ELIMINATION METHOD)

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✒✒SOLUTION::===>

°°GIVEN=>

4x+7y=29------------(1)

x+3y=11--------------(2)

✳✳Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient..

↪the coefficient of x in equation 2,multipled by 4.............

4(x+3y)=11×4

=>4x+12y=44-----------------(3)

• Both equations now have the same leading coefficient = 4

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✳✳step 2:subtract the first equation from third....

Now,

eqn(3)-eqn(1)----->

(4x+12y)-(4x+7y)=44-29

=>4x+12y-4x-7y=15

=>12y-7y=15

✳✳step 3:solve this new equation for y..

=>5y=15

$\bf\ =>y= \frac{15}{5} \\ \sf\boxed{ </p><p></p><p>=>y=3}$

✳✳ step 4: Substitute y = 3 into either Equation 1 or Equation 2 above and solve for x. We'll use Equation 2....

x+3y=11

==>x+3×3=11

==>x+9=11

==>x=11-9

==>x=2

ANSWER :- x=2 and y=3