4x-7y, - 3x² y find the product
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Answer:
-12x^3 + 21 x^2y^2 is answer of this question
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(4x-7y)x(-3x²y) = 21x²y² -12x³y
Step-by-step explanation:
Find the Product of the given equation
Equation 1 => 4x-7y
Equation 2 => -3x²y
Multiply the two given equation
==> eqn 1 ×eqn 2 = (4x-7y)x(-3x²y)
==> Multiply (-3x²y) with 4x
==> we obtain -12x³y
==> Multiply (-3x²y) with -7y
==> We obtain +21x²y²
The product of the equation is
(4x-7y)x(-3x²y) = -12x³y + 21x²y²
(4x-7y)x(-3x²y) = 21x²y² -12x³y
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