Question

(4x + 7y)
$(4x + 7y) {}^{2} - (4x - 7y) {}^{2} { =}112xy$

Answer 1

(4x+7y) (4x+7y) _ (4x_7y)(4x_7y)
= 16x×x+2(4x7y)+49y×y_(16x×x_2(4x7y)+49y×y)
=16x×x+2(4x7y)+49y×y_16x×x+2(4x7y)_49y×y
2(4x7y)+2(4x7y)z=11
4(4x7y)=11
4x7y=11/4
4x=11/4×7y. ..........(1)
(4x+7y)=0. sapose
from...(1)
11/28y+7y=0
(11+196y)/28y=0
11+196y=28y
196y_28y=_11
168y=_11
y=_11/168. y=_11/168
value of y in .....(1)
4x=11/28y
4x=11/28×_11/168
4x=11/_1.82
x=11/_1.82×4
x=11/_7.28
x=_1100/728. .-..........x=_1100/728