Math, asked by greaveyadav, 12 hours ago

4x/9+1/3+13/108x=8x+19/18​

Answers

Answered by Anonymous
3

꧁✠ Answer࿐ ✠꧂

4x/9 + 1/3 + 13x/108 = (8x+19)/18

Let us rearrange the equation

4x/9 + 13x/108 – (8x+19)/18 = -1/3

By taking LCM for 9, 108 and 18 which is 108 ((4x×12) + 13x×1 – (8x+19)6)/108 = -1/3

➪ (48x + 13x – 48x – 114)/108 = -1/3

➪(13x – 114)/108 = -1/3

By cross-multiplying

(13x – 114)3 = -108

➪39x – 342 = -108

➪39x = -108 + 342

➪ 39x = 234

➪x = 234/39 = 6

Let us verify the given equation now,

4x/9 + 1/3 + 13x/108 = (8x+19)/18

By substituting the value of ‘x’ we get,

➪4(6)/9 + 1/3 + 13(6)/108 = (8(6)+19)/18

➪24/9 + 1/3 + 78/108 = 67/18

➪ 8/3 + 1/3 + 13/18 = 67/18

➪((8×6) + (1×6) + (13×1))/18 = 67/18

➪(48 + 6 + 13)/18 = 67/18

➪67/18 = 67/18

Hence, the given equation is verified.

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