4x/9+1/3+13/108x=8x+19/18
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4x/9 + 1/3 + 13x/108 = (8x+19)/18
Let us rearrange the equation
4x/9 + 13x/108 – (8x+19)/18 = -1/3
By taking LCM for 9, 108 and 18 which is 108 ((4x×12) + 13x×1 – (8x+19)6)/108 = -1/3
➪ (48x + 13x – 48x – 114)/108 = -1/3
➪(13x – 114)/108 = -1/3
By cross-multiplying
(13x – 114)3 = -108
➪39x – 342 = -108
➪39x = -108 + 342
➪ 39x = 234
➪x = 234/39 = 6
Let us verify the given equation now,
4x/9 + 1/3 + 13x/108 = (8x+19)/18
By substituting the value of ‘x’ we get,
➪4(6)/9 + 1/3 + 13(6)/108 = (8(6)+19)/18
➪24/9 + 1/3 + 78/108 = 67/18
➪ 8/3 + 1/3 + 13/18 = 67/18
➪((8×6) + (1×6) + (13×1))/18 = 67/18
➪(48 + 6 + 13)/18 = 67/18
➪67/18 = 67/18
Hence, the given equation is verified.
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