4x[9x-{x+3x-2+(x-4x)}]
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Answered by
1
Answer:
Step-by-step explanation:
4x[9x - {x + 3x - 2 + (x - 4x)}]
= 4x[9x - {x + 3x - 2 + (-3x)}]
= 4x[9x - {x + 3x - 2 - 3x}] (opening parentheses)
= 4x[9x - {x - 2}]
= 4x[9x - x + 2]. (opening braces)
= 4x[8x + 2]
= 32 x^{2} + 8x. (opening square brackets)
Oh and Merry Christmas!
Answered by
0
Answer:
4x[9x-{x+3x-2+(x-4x)}]
= 4x[9x-{x+3x-2+3x}]
= 4x[9x-{4x-2+3x}
= 4x[ 9x-{7x-2}
= 4x[ 9x-7x-2 ]
= 4x[ 2x - 2]
= 8x -2
= 8x = 2
x = 2/8
x= 1/4 is the answer
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