Question

4x = cosec A and 4\x= cot A then. Find the value of 4{x^-1\x^​

Answer 1

Answer:

Given 4x=cosecA

x=cosecA/4

And 4/x=cotA

1/x=cotA/4

4[x²-1/x²]= 4[(cosecA/4)²

(cotA/4)²]

(putting the values of X And 1/X)

4[x²-1/x²]=4[(cosec²A/16-cot²A/16]

4[x²-1/x²]=4[(cosec²A-cot²A)/16

4[x²-1/x²]=4[1/16]

(cosec²A.l-cot²A=1)

4[x²-1/x²]=4/16=1/4

4[x²-1/x²]=1/4