Question

4x+i (3x-4)=3+i(-6)
find x, y value​

Answer 1

Answer:

ANSWER

Given 4x+i(3x−y)=3+i(−6)

comparing real and imaginary parts of R.H.S and L.H.S, we have,

4x=3⇒x=

4

3

3x−y=−6⇒3×

4

3

−y=−6

Answer 2

Answer:

x = 3/4

y = 33/4

Step-by-step explanation:

4x + i(3x - y) = 3 + i(-6)

4x + 3xi - yi = 3 - 6i

4x - 3 = yi - 6i - 3xi

4x - 3 - yi + 3xi + 6i= 0

(4x - 3) + (3x + 6 - y)i = 0

Real no. = (4x - 3) = 0 ----------(i)

Imaginary no. = (3x + 6 - y) = 0 ----------(ii)

4x - 3 = 0

4x = 3

x = 3/4

3x + 6 - y = 0

3(3/4) + 6 - y = 0

9/4 + 6 - y = 0

Taking LCM,

(9 + 24 - 4y)/4 = 0

33 - 4y = 0

4y = 33

y = 33/4