Question

4x+I(3x-y)=3+I(-6) where xand y is natural number,then find X and y.

Answer 1

Answer:

sorry but I don't know

Answer 2

Answer:

$X = \frac{3}{4} \: \: and \: \: Y = \frac{33}{4}$

Explanation:

We have,

➭4x + i (3x-y) = 3+i(-6)

Equating the real and the imaginary parts of (1), we get

➭4x = 3, 3x-y = -6

Which, on solving simultaneously,

Give $X = \frac{3}{4} \: \: and \: \: Y = \frac{33}{4}$