4x -ky = 5, 2x - 3y = 12
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➡️4x - 5y = k
Here, a1 = 4; b1 = -5 and c1 = k
➡️2x - 3y = 12
Here, a2 = 2; b2 = -3 and c2 = 12
For the 2 equations to have unique solutions,
a1/a2 ≠ b1/b2
Since k doesn't affect the condition for the equation to have a single solution, k can take any real value.
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