Question

4x square - 3x-1 find the zeroes of the following quardratic polynomials and verify the relationship between the zeroes and the cofficients​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Zeroes = 1,-1/4

Step-by-step explanation:

P(x) = 4x² - 3x - 1

⇒ 4x² - 3x - 1 = 0

⇒ 4x² - 4x + x - 1 = 0

⇒ 4x ( x - 1 ) + 1 ( x - 1 ) = 0

⇒( 4x + 1 )( x - 1 ) = 0

⇒ x = -1/4 , 1

Sum of zeroes = -b/a

⇒ 1 - 1/4 = -(-3/4)

⇒ 4 - 1 / 4 = 3/4

⇒ 3/4 = 3/4

Product of zeroes = c/a

⇒ (1)(-1/4) = -1/4

⇒ -1/4 = -1/4

Hence verified.