(4x square + 3y) by (3x square - 4y square) and verify the result for x=1 ,y=2 .
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Result is different for both
Step-by-step explanation:
Given,
(4 x² + 3 y²) and 3 x² - 4 y²)
x = 1 and y = 2
= (4 ( 1 )² + 3 ( 2 ) = ( 3 (1)² - 4 ( 2)²
= ( 4 + 6) = ( 3 - 16
= ( 10 ) = (- 13)
Result is different for both.
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