Question

4x squere +4√3+3= 0 x=?​

Answer 1

Answer:

4x^2+4√3x+3=0

4x^2+2√3x+2√3x+3=0

2x(2x+√3)+√3(2x+√3)=0

(2x+√3)(2x+√3)=0

(2x+√3)^2=0

2x+√3=0

x= -√3/2

Step-by-step explanation:

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Answer 2

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4x^2 + 4root3 + 3 = 0

=> 4x^2 + 4root3 + 3 -0 =0

=>(2x + root3)^2 -0 = 0

=> (2x + root3 + 0) ( 2x + root3 -0)

=> x = -root3/2

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