4x - [ x- { -3x - (2x - 1) - 5} ]+ 6x
please solve this
Answers
Answer:
I think this is correct answer
Hope it's help you
Please mark my answer as brainliest and follow me
Answer:
Required solution is 4(x-1)
Step-by-step explanation:
Given,4x - [ x- { -3x - (2x - 1) - 5} ]+ 6x
By BODMAS rule, we can solve this problem.
By BODMAS rule,
Bracket - Of - Division - Multiplication - Addition - Subtraction
First we are removing brackets,
4x-[x-{-3x-2x+1-5}]+6x
= 4x-[x-{-5x-4}]+6x
We are removing second brackets,
= 4x-[x+5x+4]+6x
= 4x-[6x+4]+6x
We are removing third brackets,
= 4x-6x-4+6x
= 4x-4
= 4(x-1)
Therefore, required solution is 4(x-1)
This is a problem of Simplication part of Algebra.
Some important Algebra formulas,
(a + b)² = a² + 2ab + b²
(a − b)² = a² − 2ab − b²
(a + b)³ = a³ + 3a²b + 3ab² + b³
(a - b)³ = a³ - 3a²b + 3ab² - b³
a³ + b³ = (a + b)³ − 3ab(a + b)
a³ - b³ = (a -b)³ + 3ab(a - b)
a² − b² = (a + b)(a − b)
a² + b² = (a + b)² − 2ab
a² + b² = (a − b)² + 2ab
a³ − b³ = (a − b)(a² + ab + b²)
a³ + b³ = (a + b)(a² − ab + b²)
Simplification related two more questions:
https://brainly.in/question/1813931
https://brainly.in/question/26916631
#SPJ2