4x+y{2x-(x+y)}÷y×2xy-8x
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SOLUTION 13 : Begin with x2 + xy + y2 = 1 . Differentiate both sides of the equation, getting
D ( x2 + xy + y2 ) = D ( 1 ) ,
2x + ( xy' + (1)y ) + 2 y y' = 0 ,
so that (Now solve for y' .)
xy' + 2 y y' = - 2x - y ,
(Factor out y' .)
y' [ x + 2y ] = - 2 x - y ,
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