Question

4x-y=4 3x+2y=14 by substitutions method​

Answer 1

here is your answer.

Hope you understand it ...

Answer 2

Question -

4x-y=4 and 3x+2y=14 by substitutions method.

Solution -

$4x - y = 4 \: \: ...(1)$

$3x + 2y = 14 \: \: ...(2)$

From equation (1),

$4x - y = 4$

$= > 4x = 4 + y$

$= > x = \frac{4 + y}{4}$

Now, put the value of x in equation (2).

$3x + 2y = 14$

$= > 3 \times \frac{(4 + y)}{4} + 2y = 14$

$= > \frac{(12 + 3y)}{4} + 2y = 14$

$= > \frac{12 + 3y + 8y}{4} = 14$

$= > \frac{12 + 11y}{4} = 14$

$= > 12 + 11y = 56$

$= > 11y = 56 - 12$

$= > 11y = 44$

$= > \boxed{y = 4}$

Now put the value of y in the previous value of x.

$= > x = \frac{4 + y}{4}$

$= > x = \frac{8}{4}$

$= > \boxed{x = 2}$

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