Math, asked by 11gkashyap, 8 months ago

4x-y-8=0. 2x-3y+6=0 solve by substitution method​

Answers

Answered by sarthaksubham
0

Step-by-step explanation:

4x-y-8= 2x-3y+6

4x-2x-y+3y= 6+8

2x+2y= 14

2(X+y)= 14

X+y= 7

y= 7-x

putting X vale in 4x-y= 8

4x-7+X= 8

5x= 15

X= 3

No, x+y= 7

y= 7-3

y= 4

Answered by cuterekhadhankher
0

Answer:

X=3

y=4

Step-by-step explanation:

4x-y-8=0...........(I)

2x-3y+6=0........(ii)

from eq(i)

4x-y-8=0

y=4x-8.................(iii)

in eq(ii) substitute this value

2x-3y+6=0

2x-3(4x-8)+6=0

2x-12x+24+6=0

-10x+30=0

10x=30

X=3

put this value in eq(iii)

y=4x-8=4(3)-8=12-8=4

y=4

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