Question

(4x-y+z)^² . write the answer with explanation​

Answer 1

Answer:

16x²-8xy+8xz+y²-2yz+z²

Answer 2

Given,

$(4x-y+z)^{2}$

We have to find the value of this given expression,

First we will re write the given this expression, all terms are in positive

$(4x+(-y)+z)^{2}$

We will use $(a+b+c)^{2}$ identity to simplify this given expression

$(a+b+c)^{2} =a^{2}+ b^{2}+ c^{2}+2ab+2bc+2ac$

By following the above identity, we will expand the given expression

We get,

$(4x+(-y)+z)^{2} =4\times4x^{2}+(-y)^{2}+z^{2}+2x(-y)+2(-yz)+2xz$

$= 16x^{2} +y^{2}+z^{2}-2xy-2yz+2xz$

Therefore, the answer is  $16x^{2} +y^{2}+z^{2}-2xy-2yz+2xz$.