Question

4x² - 10-3x
factorise
the
following.



plz its urgent ......​

Answer 1

Question :-

Factories it

→4 x² - 10 - 3x

Answer :-

$\: \sf{x = \frac{3 + \sqrt{169} }{8} \: or \: \frac{ 3 - \sqrt{169} }{8} } \:$

Solution :-

If we need to factories any quadratic so firstly we have to that p(x) = 0

p(x) = 4 x² - 10 - 3x = 0

→ 4 x² - 3x - 10 = 0

• a = 4 , b = -3 and c = -10

Here we have to use Shridharacharya principle

$\star \: \sf{x \: = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \: or \: \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a} } \\ \\ \rightarrow \sf{x \: = \frac{3 + \sqrt{9 + 160 } }{8} \: or \: \frac{3 - \sqrt{9 + 160} }{8} } \\ \\ \rightarrow \: \sf{x = \frac{3 + \sqrt{169} }{8} \: or \: \frac{ 3 - \sqrt{169} }{8} }$

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Answer 2

Through middle term splitting!!

Equation- 4x^2-3x-10


4x^2+( -8x+5x ) -10

4x(x-2)+2(x-2)

(4x+2)(x-2)

Factors: 4x+2 and x-2