Question

4x²-11 zeroes of polynomial

Answer 1

Step-by-step explanation:

Given:-

The Polynomial 4x^2-11

To find:-

Find the zeroes?

Solution:-

Given Polynomial is 4x^2-11

Let P(x) = 4x^2-11

To get the zeores we write P(x) = 0

=> 4x^2-11 = 0

=> 2^2x^2-11 = 0

=> (2x)^2-11 = 0

We know that

11=(√11)^2

=>(2x)^2-(√11)^2 = 0

It is in the form of a^2-b^2

Where a = 2x and b= √11

We know that

a^2-b^2 = (a+b)(a-b)

=> (2x)^2-(√11)^2 = 0

=> (2x+√11)(2x-√11) = 0

=> (2x+√11)= 0 or (2x-√11) = 0

=> 2x = -√11 or 2x =√11

=> x = -√11/2 or x = √11/2

The zeores √11/2 and -√11/2

Answer:-

The zeroes of the given Polynomial are √11/2 and -√11/2

Used Concept:-

To get the zeores of the given Polynomial P(x) then we have to equate it to zero.i.e.P(x)=0

Answer 2

Answer:

ye it is the zeroes of polynomial