Question

4x²+11x+6=0 find zeros of quadratic polynomial​

Answer 1

4x²+11x+6 = 0

=> 4x²+8x+3x+6 = 0

=> 4x(x + 2) +3(x + 2) = 0

=> (x + 2)(4x + 3) = 0

=> x+2 = 0 or 4x + 3 = 0

=> (x = -2) or (x = -3/4)

Hence, zeros of the above quadratic equation are “-2” or “-3/4” .

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Answer 2

Answer:

1. x = 3/4 = 0.750
2. x = 2

Step-by-step explanation:

(22x2 - 11x) + 6 = 0

Trying to factor by splitting the middle term

Factoring 4x2-11x+6

The first term is, 4x2 its coefficient is 4 .

The middle term is, -11x its coefficient is -11 .

The last term, "the constant", is +6

Step-1 : Multiply the coefficient of the first term by the constant 4 • 6 = 24

Step-2 : Find two factors of 24 whose sum equals the coefficient of the middle term, which is -11 .

-24 + -1 = -25

-12 + -2 = -14

-8 + -3 = -11 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and -3

4x2 - 8x - 3x - 6

Step-4 : Add up the first 2 terms, pulling out like factors :

4x • (x-2)

Add up the last 2 terms, pulling out common factors :

3 • (x-2)

Step-5 : Add up the four terms of step 4 :

(4x-3) • (x-2)

Which is the desired factorization

• (x - 2) • (4x - 3) = 0

x-2 = 0

Add 2 to both sides of the equation :

x = 2

4x-3 = 0

Add 3 to both sides of the equation :

4x = 3

Divide both sides of the equation by 4:

x = 3/4 = 0.750