Question

4x2-12ax-y2-z2-2yz+9a2

Answer 1

Formulae (required):

1.   $(a+b)^{2}=a^{2}+ab+b^{2}$

2.   $(a-b)^{2}=a^{2}+ab+b^{2}$

3.   $a^{2}-b^2=(a+b)(a-b)$

Evaluate: $4x^{2}-12ax-y^{2}-z^{2}-2yz+9a^{2}$

=         $(4x^{2}+9a^{2}-12ax)-(y^{2}+z^{2}+2yz)$

=         $(2x-3a)^{2}-(y+z)^{2}$

=        {$2x-3a+(y+z)$} {$2x-3a-(y+z)$}

=         $(2x-3a+y+z)(2x-3a-y-z)$

=         $(2x+y+z-3a)(2x-y-z-3a)$     (ans.)

ANSWER:         $(2x+y+z-3a)(2x-y-z-3a)$

Answer 2

PLZZZ see this pic.........