Question

4x2-13x+10 factorise by middle term splitting

Answer 1

Answer:

(4x-5)(x-2)

Step-by-step explanation:

4x2-13x+10

=4x2-8x-5x+10

=4x(x-2)-5(x-2)

=(4x-5)(x-2)

pls follo₩

Answer 2

Answer:

4x²-13x+10 = (x-2)(4x-5)

Step-by-step explanation:

Given polynomial is 4x²-13x+10

To find,

The factors of the polynomial 4x²-13x+10 by middle term splitting

Solution:

We have, 4x²-13x+10

To split the middle term we need to find two integers such that

sum  = -13 and product = 4×10 = 40

The pair of factors of 40 are  (1, 40), (2, 20), (4, 10), and (5, 8).

From this, we can get two numbers -5 and -8 such that

-5+-8 = -13 and (-5) ×(-8) = +40

4x²-13x+10 = 4x²-5x -8x+10

= x(4x - 5) -2(4x - 5)

= (x-2)(4x-5)

∴ 4x²-13x+10 = (x-2)(4x-5)

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