Question

4x2 -2(a2+b2)x + a2b2 =0

Answer 1

4x^2-2(a^2+b^2)x+a^2b^2=0

4x^2-2a^2x-2b^2x+a^2b^2=0
2x(2x-a^2)-b^2(2x-a^2)=0

(2x-a^2)(2x-b^2)=0

2x-a^2=0 or 2x-b^2=0

2x=a^2 or 2x=b^2

x=a^2/2 or x= b^2/2

Answer 2

Answer:

Step-by-step explanation:

Solution :-

Here, we have

4x² - 2(a² + b²)x + a²b² = 0

Therefore,

Constant term = a²b² = a² × b²

Coefficient of middle term = - 2(a² + b²)

Then,

⇒ 4x² - 2(a² + b²)x + a²b² = 0

⇒ 4x² - 2a²x - 2b²x + a²b² = 0

⇒ (4x² - 2a²x) - (2b²x - a²b²) = 0

⇒ 2x(2x - a²) - b²(2x - a²) = 0

⇒ (2x - a²) (2x - b²) = 0

⇒ (2x - a²) = 0 or (2x - b²) = 0

⇒ x = a²/2 or x = b²/2

Hence, x = a²/2 or x = b²/2