Question

4x2-2(a2+b2)x+a2b2=0..
*solve by quadratic formula*​

Answer 1

Answer:

Solve 4x2-2(a2+b2)x+a2b2=0 find the value of x

Step-by-step explanation:

a= 4

b= -2(a2+b2)

c= a2b2

Using Discriminant formula,

D= b2-4ac

[-2(a2+b2)]2-4 x4xa2b2

4(a4+b4+2a2b2)-16a2b2

(2a2-2b2)2

x= (-b±D)/ 2a

x= [2(a2+b2)+2(a2-b2)]/8 = 4a2/8 = a2/2

x= [2(a2+b2)-2(a2-b2)]/8 = 4b2/8 = b2/2