4x2 – 20x + 25 = 0 have
Real and Distinct roots
Real and Equal roots
Real roots
No Real roots
Answers
Answer :
The answer is :
Real and Equal roots
Given :
The quadratic equation is :
- 4x² - 20x + 25 = 0
To Find :
- Whether the given equation has :
- Real and distinct roots or
- Real and equal roots or
- Real roots or
- No real roots
Concept used here :
Discriminant of a quadratic equation (b² - 4ac) :
- If ax² + bx + c is a quadratic equation then b²-4ac is called the discriminant of that equation.
- From the discrimiant we can examine the nature of roots of the given quadratic equation
- Condition of discriminant →
- If b² - 4ac > 0 , then two distinct and real roots are there
- If b² - 4ac = 0 , then two real and equal are there
- if b² - 4ac ≥ 0 , then real roots are there
- If b² - 4ac < 0 , then no real root is there.
Solution :
Let us consider from the given equation :
a = 4 , b = -20 , and c = 25
Therefore , the discriminant D will be
Thus discriminant , b² - 4ac = 0
So the given equation has real and equal roots
Answer:
Step-by-step explanation:
Solution :-
Given Equation,
= 4x² - 20x + 25 = 0
On comparing the equation with ax² + bx + c = 0, we get
Here, a = 4 , b = -20 , and c = 25
We know that,
Discriminant, D = b² - 4ac
D = b² - 4ac
⇒ D = (- 20)² - 4 × 4 × 25
⇒ D = 400 - 400
⇒ D = 0
Since, b² - 4ac = 0
Hence, the given equation has real and equal roots.
More About the Topic :-
For the quadratic equation ax² + bx + c = 0, the expression b² - 4ac is known as discriminant i.e Discriminant, D = b² - 4ac
Nature of roots of a quadratic equation:-
(i). If b² - 4ac > 0, the quadratic equation has two distinct real roots.
(ii). If b² - 4ac = 0, the quadratic equation has two equal real roots.
(iii). If b² - 4ac < 0, the quadratic equation has no real roots.