Question

(4x2 + 24xy + 3y2) *(x2 – xy + y2)​

Answer 1

Step-by-step explanation:

Let ‘E’ be the required expression. Then, we have x2 – xy + y2– x + y + 3 – E = – x2 + 3y2 – 4xy + 1 Therefore, E = (x2 – xy + y2– x + y + 3) – (- x2 + 3y2 – 4xy + 1) = x2 – xy + y2– x + y + 3 + x2 – 3y2 + 4xy – 1 Collecting positive and negative like terms together, we get = x2 + x2– xy + 4xy + y2– 3y2 – x + y + 3 – 1 = 2x2+ 3xy- 2y2– x + y + 2Read more on Sarthaks.com - https://www.sarthaks.com/682968/what-should-be-subtracted-from-x-2-xy-y-2-x-y-3-to-obtain-x-2-3y-2-4xy-1?show=682971#a682971