Question

4x²+3x-5=0 by the method of Quadratic ​

Answer 1

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4x²+3x-5=0 by the method of Quadratic

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$x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac }   }{2a}$

here a=4,b=3,c=-5

$x = \frac{ - 3 ± \sqrt{ ({3})^{2} - 4(4)( - 5)}   }{2 \times 4}$

$x = \frac{ - 3 ± \sqrt{9 + 80}   }{8}$

$x = \frac{ - 3 ±  \sqrt{89} }{8}$

Hope it helps you..!!!

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