Math, asked by spidy6093, 11 months ago

4x2+4/3 2+3=0


solve the question by completing the square method

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Answered by igaurav23
2

Answer:

4 {x}^{2}  + 2 \sqrt{3} x + 2 \sqrt{3} x + 3  = 0\\ 2x(2x +  \sqrt{3} ) +  \sqrt{3} (2x +  \sqrt{3} ) = 0 \\ (2x +  \sqrt{3} )(2x +  \sqrt{3} ) = 0 \\ 2x +  \sqrt{3}  = 0 \:  \:  \:  \: 2x =  -  \sqrt{3}  \:  \:  \: x =  \frac{ -  \sqrt{3} }{2}  \\ similarly \: x =  \frac{ -  \sqrt{3} }{2}

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