Math, asked by sanhitahalder07, 6 months ago

4x²+4√3x+3=0 .. pls solve it fast it's urgent​

Answers

Answered by Sankalp050
7

Answer:

4 {x}^{2}  + 4 \sqrt{3} x + 3 = 0 \\  \\ 4 {x}^{2}  + 2 \sqrt{3}  x + 2 \sqrt{3} x + 3 = 0 \\  \\ 2x(2x +  \sqrt{3} x) +  \sqrt{3} (2x +  \sqrt{3} x) = 0 \\  \\ (2x +  \sqrt{3} x)(2 x+  \sqrt{3} x) = 0 \\  \\  \\  {(2x +  \sqrt{3} )}^{2}  = 0 \\  \\  \\ 2x +  \sqrt{3}  = 0 \\  \\ 2 x =  -  \sqrt{3}  \\  \\  \\ x =  \frac{ -  \sqrt{3} }{2}

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