Question

4x²-4a²x+(a⁴-b⁴)=0
solve this question by quadratic formula {D=b²-4ac} & {x=[-b(+-)√D]/(2a)}.........
please solve this question.......​

Answer 1

Answer:

4x²-4a²x+(a⁴-b⁴)=0

a=4

b=-4a²

c=a⁴-b⁴

D=

{b}^{2} - 4acb

2

−4ac

(-4a²)²-4×4×(a⁴-b⁴)

16a⁴-16a⁴+16b⁴

D=16b⁴

x=-b±√D/2a

=-(-4a²)±4a²/2×4

=4a²±4a²/8

x=4a²+4a²/8

=8a²/8

=a²

x=4a²-4a²/8

=0/8

=0

the roots of the given quadratic equations is a² & 0......