Question

4x² + 4ax + (a^2-b^ 2) =0,​

Answer 1

Answer:

x= (a+b)/2. or, (a-b)/2

Step-by-step explanation:

4x² + 4ax + (a^2-b^ 2) =0

=> 4x² + 2(a+b) x - 2(a-b)x + (a+b)(a-b) = 0

=> 2x {2x - (a+b)} - (a-b) {2x - (a+b)} =0

=> {2x - (a+b)} {2x - (a-b)} =0

therefore,

{2x - (a+b)} =0. or, {2x - (a-b)} =0

2x =(a+b). or, 2x = (a-b)

x= (a+b)/2. or, x = (a-b)/2