4x² + 4ax + (a^2-b^ 2) =0,
Answers
Answered by
4
Answer:
x= (a+b)/2. or, (a-b)/2
Step-by-step explanation:
4x² + 4ax + (a^2-b^ 2) =0
=> 4x² + 2(a+b) x - 2(a-b)x + (a+b)(a-b) = 0
=> 2x {2x - (a+b)} - (a-b) {2x - (a+b)} =0
=> {2x - (a+b)} {2x - (a-b)} =0
therefore,
{2x - (a+b)} =0. or, {2x - (a-b)} =0
2x =(a+b). or, 2x = (a-b)
x= (a+b)/2. or, x = (a-b)/2
Similar questions