Question

4x2+4bx-(a2-b2)=0 solve by factorization

Answer 1

Answer:

4x×2+4bx-(a2-b2)=0

4×2+2(a+b) x-2 (a-b) x-(a2-b2)=0

2×(2×a+b) - (a-b)(2x+a+b)=0

(2x-(a-b)) (2x+a+b)=0

Therefore ,

2x-(a-b)=0

2x=a-b

x=a-b/2

or,

2x+a+b=0

2x=-(a+b)

x=-(a+b)/2

Hence , X=(a-b)/2 or X= -(a+b)/2