Question

4x²+4bx-(a²-b²)=0solve it by squaring method
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Answer 1

Answer:

x = (a-b)/2

Step-by-step explanation:

4x²+4bx-(a²-b²)=0

=> (2x)^2 + 2(2x)(b) = a^2 - b^2

Add b^2 both the side of the equation to complete the square on LHS

=> (2x)^2 + 2(2x)(b) + b^2 = a^2 - b^2 + b^2

=> (2x + b)^2 = a^2

=> 2x + b = a

=> 2x = a -b

=> x = (a-b)/2

Hope this will help U

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