(4x2
+ 4xy + y2
) ÷ (2x + y) =
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0
Answer:
(4x^2+4xy+y^2)÷(2x+y)
[(4x^2+4xy+y^2)=(2x+y)^2]
(2x + y)×(2x + y)÷ (2x + y)=2x+y
Answered by
0
Step-by-step explanation:
it is in a+b whole square (a+b)^2= (a+b)(a+b) I have spliced and canceled or divided by 2x+y
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