Question

4x²+4xy+y²

help me, placeeee​

Answer 1

Answer:

4x²+4xy+y²

Step-by-step explanation:

Comparing the equation 4x2 + 4xy + y2 = 0

O with ax? + 2hxy + by2 = 0, we get, a = 4, 2 h = 4 i,e, h = 2, and b = 1 :: 92 - ab = (2)2 - 4(1) = 4 - 4 = 0

Since the equation 4x2 + 4xy + y2 = 0 is a homogeneous equation of second degree and h2 - ab = 0, the given equation represents a pair of lines which are real and coincident.